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Orsay's a question worth exploring


: 12345678910111213141516171819202122232425262728293 03132333435 He asked Shanghai Shanghai with small children 3x4 (3 rows, 4) rectangular box of 12 numbers. Them and is 2010. So the largest number of this number 12 is. This question is worth exploring why I believe that, first,MBTシューズ 販売店, because the flexible solution of solving the problem. Provide students with a broad space of thinking, help students to be innovative, to explore; second, because the problem asks, Solution of a problem according to meaning, let any number of boxes out of 12 (3 rows. 4),Beats By Dre Headphones, look at what the arrangement 12 the number of rules. Such as: Through observation, we found the following few rules: ① the four numbers in each row, from left to right, from small to large order of priority,air jordan high heels, after a large number than the previous number 1; ② three in each column number, from top to bottom, from small to large order of priority,herve leger sale, the next number on a large number of more than 7; ③ each column, the middle number,Salvatore Ferragamo outlet, exactly equal to this column, the lower the average of two numbers. Then any number of boxes out of l2 to see whether the arrangement of the law. The observation, in line with the arrangement of the law. At this time, we can use the answers to this question of law. ,: ③ can be extrapolated from the law, and equal to the number of the middle line on the next two rows and the average. In other words, the 12 number 'is equal to the sum of the number of the middle row and 3 times. From this knowledge, the required number of intermediate line 12 and the number is 2010 + 3 = 670. ① known by the law, the last line number is (670 +3 +2 +1) ÷ 4 = 169. ② known by the law. The last column is the number 169 +7 = 176. This number is the largest number of 12 is 176. Solution two change the angle, once again observe a box above the number 12, but also found that: 10 +27 = 11 +26 = 12 +25 = 13 +24 = 18 +19 = 17 +20. That ① the box out of the 12 number, can be divided into 6 equal groups (each group has two numbers); - ② minimum number and maximum number of them as a group; large numbers of sub-fractional and sub-group I. . ... * The middle two numbers as a group; ③ number one difference between the minimum and maximum number of 17. ① known by the groups of numbers and the 2010 + 6 = 335, ie, minimum and maximum number and the number is 335; the ③ know, the difference between these two numbers is 17. And the difference from the known solution of the problem, which is the largest number (335 +17) ÷ 2 = l76. Solution three change the angle, once again observe a box above the number 12. We can also find: 11 + 12 = 10 = 17 +20,25 +13,18 +19 +27 +26 = 24. That ① the second, three in number and 6 is equal to the first, four in number and 6; ② the first, four in number and 6, can be divided into three equal groups; ③ first First, four of the minimum number and maximum number for a group, and the difference between these two numbers 17. ① know from the first, four in number and 6 is 2010 +2 = 1005; by the ② know. Each of the two data and the 1oo5 +3 = 335; ③ know by the first, four in the maximum number is (335 +17) ÷ 2 = 176. Also is the desired number of 12 is the maximum number of 176. Solution four unconventional answer to this question is: the selected base, making it up to solve. For simplicity, we have selected the following 12 minimum number of base for the calculation: 123489101115161718 is the 12 and the number of 114, with the required number of 12 and a difference of 2010-114 = 1896, indicating the difference between each number 1896 +12 = 158. Thus we can see, the biggest number is 18 +158 = 176. Obviously. Solution of four creative, and thinking is simple, I count you can. But the number 12 can not find this in a rectangular box within. The reason is simple, the number 176 to 176, each line number 7, there are 176 + 7 = 25 ... ... 1. Therefore, the problem may be in the condition More articles related to topics：


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